0=3x^2+10x-828

Solution for 0=3x^2+10x-828 equation:

0=3x^2+10x-828

We move all terms to the left:

0-(3x^2+10x-828)=0

We add all the numbers together, and all the variables

-(3x^2+10x-828)=0

We get rid of parentheses

-3x^2-10x+828=0

a = -3; b = -10; c = +828;
Δ = b2-4ac
Δ = -102-4·(-3)·828
Δ = 10036
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{10036}=\sqrt{4*2509}=\sqrt{4}*\sqrt{2509}=2\sqrt{2509}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-10)-2\sqrt{2509}}{2*-3}=\frac{10-2\sqrt{2509}}{-6}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-10)+2\sqrt{2509}}{2*-3}=\frac{10+2\sqrt{2509}}{-6}
$